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解决已经删除的用户依旧能登录的bug

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This commit is contained in:
季圣华
2020-01-01 14:58:11 +08:00
parent e56f6d6724
commit 55cd8f04f0
1 changed files with 5 additions and 4 deletions
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9
src/main/java/com/jsh/erp/service/user/UserService.java
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@@ -229,7 +229,7 @@ public class UserService {
List<User> list = null;
try {
UserExample example = new UserExample();
example.createCriteria().andLoginameEqualTo(username);
example.createCriteria().andLoginameEqualTo(username).andStatusEqualTo(BusinessConstants.USER_STATUS_NORMAL);
list = userMapper.selectByExample(example);
} catch (Exception e) {
logger.error(">>>>>>>>访问验证用户姓名是否存在后台信息异常", e);
@@ -242,7 +242,8 @@ public class UserService {
try {
UserExample example = new UserExample();
example.createCriteria().andLoginameEqualTo(username).andPasswordEqualTo(password);
example.createCriteria().andLoginameEqualTo(username).andPasswordEqualTo(password)
.andStatusEqualTo(BusinessConstants.USER_STATUS_NORMAL);
list = userMapper.selectByExample(example);
} catch (Exception e) {
logger.error(">>>>>>>>>>访问验证用户密码后台信息异常", e);
@@ -257,7 +258,7 @@ public class UserService {
public User getUserByUserName(String username)throws Exception {
UserExample example = new UserExample();
example.createCriteria().andLoginameEqualTo(username);
example.createCriteria().andLoginameEqualTo(username).andStatusEqualTo(BusinessConstants.USER_STATUS_NORMAL);
List<User> list=null;
try{
list= userMapper.selectByExample(example);
@@ -316,7 +317,7 @@ public class UserService {
public Long getIdByLoginName(String loginName) {
Long userId = 0L;
UserExample example = new UserExample();
example.createCriteria().andLoginameEqualTo(loginName);
example.createCriteria().andLoginameEqualTo(loginName).andStatusEqualTo(BusinessConstants.USER_STATUS_NORMAL);
List<User> list = userMapper.selectByExample(example);
if(list!=null) {
userId = list.get(0).getId();