优化角色的功能权限的分配逻辑
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@@ -2,10 +2,7 @@ package com.jsh.erp.service;
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import com.alibaba.fastjson.JSONObject;
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import com.jsh.erp.constants.BusinessConstants;
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import com.jsh.erp.datasource.entities.Function;
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import com.jsh.erp.datasource.entities.FunctionEx;
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import com.jsh.erp.datasource.entities.FunctionExample;
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import com.jsh.erp.datasource.entities.User;
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import com.jsh.erp.datasource.entities.*;
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import com.jsh.erp.datasource.mappers.FunctionMapper;
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import com.jsh.erp.datasource.mappers.FunctionMapperEx;
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import com.jsh.erp.exception.JshException;
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@@ -20,9 +17,7 @@ import org.springframework.web.context.request.ServletRequestAttributes;
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import javax.annotation.Resource;
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import javax.servlet.http.HttpServletRequest;
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import java.util.ArrayList;
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import java.util.Date;
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import java.util.List;
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import java.util.*;
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@Service
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public class FunctionService {
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@@ -33,10 +28,16 @@ public class FunctionService {
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@Resource
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private FunctionMapperEx functionMapperEx;
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@Resource
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private UserService userService;
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@Resource
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private UserBusinessService userBusinessService;
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@Resource
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private SystemConfigService systemConfigService;
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@Resource
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private LogService logService;
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@@ -193,7 +194,7 @@ public class FunctionService {
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return list;
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}
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public List<Function> findRoleFunction(String pnumber)throws Exception{
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public List<Function> findRoleFunction(String pnumber, List<Long> funIdList)throws Exception{
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List<Function> list=null;
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try{
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Boolean multiLevelApprovalFlag = systemConfigService.getMultiLevelApprovalFlag();
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@@ -206,6 +207,9 @@ public class FunctionService {
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criteria.andUrlNotEqualTo("/workflow");
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}
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}
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if(funIdList!=null && funIdList.size()>0) {
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criteria.andIdIn(funIdList);
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}
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example.setOrderByClause("Sort");
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list =functionsMapper.selectByExample(example);
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}catch(Exception e){
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@@ -228,4 +232,103 @@ public class FunctionService {
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}
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return list;
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}
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/**
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* 获取当前用户所属的租户所拥有的功能id列表
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* @return
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*/
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public List<Long> getCurrentTenantFunIdList() throws Exception {
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List<Long> funIdList = new ArrayList<>();
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Long roleId = 0L;
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String fc = "";
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User userInfo = userService.getCurrentUser();
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//只返回非租户的map,如果是租户就返回空数组
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if(!userInfo.getId().equals(userInfo.getTenantId())) {
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//获取当前用户所有的角色id
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List<UserBusiness> roleList = userBusinessService.getBasicData(userInfo.getTenantId().toString(), "UserRole");
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if(roleList!=null && roleList.size()>0){
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String value = roleList.get(0).getValue();
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if(StringUtil.isNotEmpty(value)){
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String roleIdStr = value.replace("[", "").replace("]", "");
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roleId = Long.parseLong(roleIdStr);
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}
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}
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//当前用户所拥有的功能列表,格式如:[1][2][5]
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List<UserBusiness> funList = userBusinessService.getBasicData(roleId.toString(), "RoleFunctions");
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if(funList!=null && funList.size()>0){
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fc = funList.get(0).getValue();
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}
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if(StringUtil.isNotEmpty(fc)) {
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fc = fc.substring(1, fc.length() - 1);
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fc = fc.replace("][",",");
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funIdList = StringUtil.strToLongList(fc);
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}
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}
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return funIdList;
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}
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/**
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* 获取当前用户所属的租户所拥有的功能id的map
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* @return
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*/
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public Map<Long, Long> getCurrentTenantFunIdMap() throws Exception {
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Map<Long, Long> funIdMap = new HashMap<>();
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List<Long> list = getCurrentTenantFunIdList();
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if(list.size()>0) {
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for (Long funId : list) {
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funIdMap.put(funId, funId);
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}
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return funIdMap;
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} else {
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return null;
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}
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}
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/**
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* 获取当前用户所拥有的功能id列表
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* @return
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*/
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public List<Long> getCurrentUserFunIdList() throws Exception {
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List<Long> funIdList = new ArrayList<>();
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Long roleId = 0L;
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String fc = "";
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User userInfo = userService.getCurrentUser();
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//获取当前用户所有的角色id
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List<UserBusiness> roleList = userBusinessService.getBasicData(userInfo.getId().toString(), "UserRole");
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if(roleList!=null && roleList.size()>0){
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String value = roleList.get(0).getValue();
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if(StringUtil.isNotEmpty(value)){
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String roleIdStr = value.replace("[", "").replace("]", "");
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roleId = Long.parseLong(roleIdStr);
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}
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}
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//当前用户所拥有的功能列表,格式如:[1][2][5]
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List<UserBusiness> funList = userBusinessService.getBasicData(roleId.toString(), "RoleFunctions");
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if(funList!=null && funList.size()>0){
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fc = funList.get(0).getValue();
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}
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if(StringUtil.isNotEmpty(fc)) {
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fc = fc.substring(1, fc.length() - 1);
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fc = fc.replace("][",",");
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funIdList = StringUtil.strToLongList(fc);
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}
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return funIdList;
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}
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/**
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* 获取当前用户所拥有的功能id的map
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* @return
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*/
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public Map<Long, Long> getCurrentUserFunIdMap() throws Exception {
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Map<Long, Long> funIdMap = new HashMap<>();
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List<Long> list = getCurrentUserFunIdList();
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if(list.size()>0) {
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for(Long funId: list) {
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funIdMap.put(funId, funId);
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}
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return funIdMap;
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} else {
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return null;
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}
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}
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}
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